# Line slope calculator 8x-5y=-2

**Straight line given by points A[1; 2] and B[6; 10]**

## Calculation:

**Slope-intercept form of line:**y = 1.6x+0.4

**Canonical form of the line equation:**8x-5y+2 = 0

**Parametric form of the line equation:**

x = 5t+1

y = 8t+2 ; t ∈ R

**Slope:**m = 1.6

**Slope angle of line: φ =**57°59'41″ = 1.0122 rad

**X intercept:**x

_{0}= -0.25

**Y intercept:**y

_{0}= q = 0.4

**Distance line from the origin:**d

_{0}= 0.212

**The length of the segment AB: |AB| =**9.434

**Vector: AB =**(5; 8)

**Normal vector: n =**(8; -5)

**Midpoint of the segment AB: M =**[3.5; 6]

**Perpendicular Bisector equation:**5x+8y-65.5 = 0

**Vector OA = (1; 2) ; |OA| = 2.2361**

**Vector OB = (6; 10) ; |OB| = 11.6619**

**Scalar product OA .OB = 26**

**Angle ∠ AOB = 4°23'55″ = 0.0768 rad**